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IBM Programming with IBM Enterprise PL/I Sample Questions:
1. Given the following program, which subroutine improperly uses pointers to address memory and could lead to data corruption or an exception?
A) SUB2
B) PROC OPTIONS(MAIN);
DCL
1 X,
2 X1 CHAR(76),
2 X2 PIC'9999';
DCL Y CHAR(20);
CALL SUB1( ADDR(X));
CALL SUB2( ADDR(X));
CALL SUB3( ADDR(X));
CALL SUB4( ADDR(X));
SUB 1: PROC( P);
DCL P POINTER;
DCL
1 XBASED(P),
2 X1 CHAR(76),
2 X2 PIC'9999'
X = ";
END;
SUB2: PROC( P);
DCL P POINTER;
DCL
1 X BASED(P),
2 X 1 PIC'(76)X'
2 X 2 PIC'9999'
X = ";
END;
SUB3: PROC( P);
DCL P POINTER;
DCL X CHAR(60) BASED(P);
X = ";
END;
SUB4: PROC( P );
DCL P POINTER;
DCLX CHAR(100) BASED(P);
X = ";
END; END;
C) SUB1
D) SUB4
E) SUB3
2. CORRECT TEXT
Which of the following is a DEC FIXED constant?
A) '100010'B
B) 1000.10
C) 100010B
D) 1E+03
3. CORRECT TEXT
If the physical dataset referred to by DDOUT has a maximum record length of 196 and a
RECFM=V, what happens after executing the following code?
DCL DDOUT FILE RECORD OUTPUT;
DCL OUT_CHAR CHAR(500) VARYING INIT((220)' ');
OPEN FILE(DDOUT);
WRITE FILE(DDOUT) FROM(OUT_CHAR);
A) One record with a length of 196 will be written to the output file.
B) One record with a length of 500 will be written to the output file.
C) One record with a length of 220 will be written to the output file.
D) An error will occur because of mismatch of record length.
4. CORRECT TEXT
If the physical dataset referred to by DDOUT has a maximum record length of 200 and RECFM=V,
what happens alter executing the following code?
DCL DDOUT FILE RECORD OUTPUT;
DCLI BIN FIXED(15) INIT(0);
DCL 1 OUTSTR,
2 A CF-IAR(150),
2 B CI-IAR(46);
OPEN FILE(DDOUT);
DO It 1 TO 10;
WRITE FILE(DDOUT) FROM(OUTSTR);
END;
A) Nothing will be written to the output file.
B) At runtime, an error will occur because of mismatch of record length.
C) At compile time, an error will occur because of mismatch of record length.
D) 10 records will be written to the output file.
5. CORRECT TEXT
What is the value of B after executing the following code?
DCL A CHAR(10) INIT('123abCDEFG');
DCLB BIN FIXED(31) INIT(5);
B = INDLX(A,'AB');
A) 0
B) 4
C) 1
D) 11
Solutions:
| Question # 1 Answer: E | Question # 2 Answer: B | Question # 3 Answer: D | Question # 4 Answer: D | Question # 5 Answer: A |
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